This is once again due to the current-change-resisting property of the inductor. The current through D1 and L2 increases and until C1 voltage hits 0, then starts to decrease from there, thus charging C1 to a positive voltage. However, no current flow through L1 as there is no base current. Next, current flows through D1 and L2 to increase the voltage of the negatively charged C1. Since L2 and C1 forms an LC circuit, at some point, the C1 voltage is too negative that the current stops flowing.Now, the base current suddenly drops, causing the L1 current to drop drastically until the current through L1 hits 0. C1 cannot discharge into the ground as D1 is blocking, thus it goes through the base of the transistor, allowing L1 current to continue flowing. This induces a current through L2 to charge the C1 to a negative voltage. Due to the inductance of L1, the current slowly increases through L1. This allows a current to flow through L1. A small current flows through R1 into the transistor's base.
0 Comments
Leave a Reply. |
AuthorWrite something about yourself. No need to be fancy, just an overview. ArchivesCategories |